Harddisk space occupation calculation
The DVR data harddisk occupation per channel/hour is as following table according to different bit rate and resolution:
(The table is only for reference, the real product shall prevail)
Unit: Megabyte /Channel/Hour.
According to this table, for a 4-channel DVR and 1TB hard disk, if the resolution is CIF and video bit rate is “excellent”, then the mainframe can record the days in following formula 24 hours per day:
N = 1000G * 1000 / (4 * 300 * 24) = 34.7 days
Where, N is the number of days, 1000G * 1000 = 1000000MB is the total capacity of the harddisk, 4 * 300 * 24 = 28800 is the harddisk space occupied by 4 cameras 24 hours per day.
The data from different environment, signal source and bit rate will be different, so the data can only serve for reference.